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11343410303 is a prime number
BaseRepresentation
bin10101001000001111…
…01011010001111111
31002021112121221121112
422210013223101333
5141212403112203
65113332352235
7551046253031
oct124407532177
932245557545
1011343410303
1148a1072065
122246a7567b
1310ba114304
14798743c51
15465cc56d8
hex2a41eb47f

11343410303 has 2 divisors, whose sum is σ = 11343410304. Its totient is φ = 11343410302.

The previous prime is 11343410249. The next prime is 11343410317. The reversal of 11343410303 is 30301434311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11343410303 - 28 = 11343410047 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11343410203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5671705151 + 5671705152.

It is an arithmetic number, because the mean of its divisors is an integer number (5671705152).

Almost surely, 211343410303 is an apocalyptic number.

11343410303 is a deficient number, since it is larger than the sum of its proper divisors (1).

11343410303 is an equidigital number, since it uses as much as digits as its factorization.

11343410303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 11343410303 its reverse (30301434311), we get a palindrome (41644844614).

The spelling of 11343410303 in words is "eleven billion, three hundred forty-three million, four hundred ten thousand, three hundred three".