Base | Representation |
---|---|
bin | 10000100000011100000… |
… | …000101101011100000110 |
3 | 11000102221012022021202202 |
4 | 100200130000231130012 |
5 | 122041112334024220 |
6 | 2225035331034502 |
7 | 144645015040301 |
oct | 20403400553406 |
9 | 4012835267682 |
10 | 1134341314310 |
11 | 3a8087110796 |
12 | 163a1473ba32 |
13 | 82c776c66b9 |
14 | 3cc8c311b38 |
15 | 1e7907c0275 |
hex | 1081c02d706 |
1134341314310 has 8 divisors (see below), whose sum is σ = 2041814365776. Its totient is φ = 453736525720.
The previous prime is 1134341314297. The next prime is 1134341314313. The reversal of 1134341314310 is 134131434311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×11343413143102 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1134341314313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56717065706 + ... + 56717065725.
It is an arithmetic number, because the mean of its divisors is an integer number (255226795722).
Almost surely, 21134341314310 is an apocalyptic number.
1134341314310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1134341314310 is a deficient number, since it is larger than the sum of its proper divisors (907473051466).
1134341314310 is a wasteful number, since it uses less digits than its factorization.
1134341314310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 113434131438.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 1134341314310 its reverse (134131434311), we get a palindrome (1268472748621).
The spelling of 1134341314310 in words is "one trillion, one hundred thirty-four billion, three hundred forty-one million, three hundred fourteen thousand, three hundred ten".
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