11343420113 has 4 divisors (see below), whose sum is σ = 11356941120. Its totient is φ = 11329899108.

The previous prime is 11343420091. The next prime is 11343420131. The reversal of 11343420113 is 31102434311.

11343420113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11343420113 - 2¹² = 11343416017 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (11343420713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6759245 + ... + 6760922.

It is an arithmetic number, because the mean of its divisors is an integer number (2839235280).

Almost surely, 2^11343420113 is an apocalyptic number.

It is an amenable number.

11343420113 is a deficient number, since it is larger than the sum of its proper divisors (13521007).

11343420113 is an equidigital number, since it uses as much as digits as its factorization.

11343420113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13521006.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 11343420113 its reverse (31102434311), we get a palindrome (42445854424).

The spelling of 11343420113 in words is "eleven billion, three hundred forty-three million, four hundred twenty thousand, one hundred thirteen".