Base | Representation |
---|---|
bin | 11001110010101011110110… |
… | …100010001001100000000111 |
3 | 112212122012112222221012220002 |
4 | 121302223312202021200013 |
5 | 104332001241420344221 |
6 | 1041130543513031515 |
7 | 32615231530542632 |
oct | 3162536642114007 |
9 | 485565488835802 |
10 | 113434222434311 |
11 | 33164202381729 |
12 | 1088038b6b559b |
13 | 4b3aa5553690c |
14 | 200236213ac19 |
15 | d1aa3eeda80b |
hex | 672af6889807 |
113434222434311 has 4 divisors (see below), whose sum is σ = 114557333547624. Its totient is φ = 112311111321000.
The previous prime is 113434222434241. The next prime is 113434222434343.
113434222434311 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113434222434311 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113434222434361) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 561555556505 + ... + 561555556706.
It is an arithmetic number, because the mean of its divisors is an integer number (28639333386906).
Almost surely, 2113434222434311 is an apocalyptic number.
113434222434311 is a deficient number, since it is larger than the sum of its proper divisors (1123111113313).
113434222434311 is a wasteful number, since it uses less digits than its factorization.
113434222434311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1123111113312.
The product of its digits is 165888, while the sum is 38.
The spelling of 113434222434311 in words is "one hundred thirteen trillion, four hundred thirty-four billion, two hundred twenty-two million, four hundred thirty-four thousand, three hundred eleven".
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