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11343430213 = 47947254857
BaseRepresentation
bin10101001000001111…
…10000001001000101
31002021112122221220221
422210013300021011
5141212404231323
65113333024341
7551046365053
oct124407601105
932245587827
1011343430213
1148a1086015
122246a850b1
1310ba1203ab
1479874b1d3
15465ccb55d
hex2a41f0245

11343430213 has 8 divisors (see below), whose sum is σ = 11597058432. Its totient is φ = 11090313696.

The previous prime is 11343430201. The next prime is 11343430223. The reversal of 11343430213 is 31203434311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11343430213 - 233 = 2753495621 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11343430223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 82920 + ... + 171937.

It is an arithmetic number, because the mean of its divisors is an integer number (1449632304).

Almost surely, 211343430213 is an apocalyptic number.

It is an amenable number.

11343430213 is a deficient number, since it is larger than the sum of its proper divisors (253628219).

11343430213 is an equidigital number, since it uses as much as digits as its factorization.

11343430213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 255851.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 11343430213 its reverse (31203434311), we get a palindrome (42546864524).

The spelling of 11343430213 in words is "eleven billion, three hundred forty-three million, four hundred thirty thousand, two hundred thirteen".

Divisors: 1 47 947 44509 254857 11978279 241349579 11343430213