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113434433420000 = 255471173658723
BaseRepresentation
bin11001110010101100000011…
…000110111111101011100000
3112212122020002200221101211212
4121302230003012333223200
5104332002204423420000
61041131020451125252
732615240002103360
oct3162540306775340
9485566080841755
10113434433420000
1133164300488370
121088042a2a3828
134b3aa8a169314
14200238217c9a0
15d1aa537b4c35
hex672b031bfae0

113434433420000 has 240 divisors, whose sum is σ = 347926098909312. Its totient is φ = 35356186560000.

The previous prime is 113434433419999. The next prime is 113434433420039. The reversal of 113434433420000 is 24334434311.

It is a Harshad number since it is a multiple of its sum of digits (32).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 35289362 + ... + 38369361.

Almost surely, 2113434433420000 is an apocalyptic number.

113434433420000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

113434433420000 is an abundant number, since it is smaller than the sum of its proper divisors (234491665489312).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113434433420000 is an equidigital number, since it uses as much as digits as its factorization.

113434433420000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 73658771 (or 73658748 counting only the distinct ones).

The product of its (nonzero) digits is 41472, while the sum is 32.

Adding to 113434433420000 its reverse (24334434311), we get a palindrome (113458767854311).

The spelling of 113434433420000 in words is "one hundred thirteen trillion, four hundred thirty-four billion, four hundred thirty-three million, four hundred twenty thousand".