1134403211133 has 12 divisors (see below), whose sum is σ = 1665444423708. Its totient is φ = 743870957760.

The previous prime is 1134403211119. The next prime is 1134403211147. The reversal of 1134403211133 is 3311123044311.

1134403211133 is a `hidden beast` number, since 1 + 1 + 3 + 440 + 3 + 211 + 1 + 3 + 3 = 666.

It is an interprime number because it is at equal distance from previous prime (1134403211119) and next prime (1134403211147).

It can be written as a sum of positive squares in 2 ways, for example, as 97482577284 + 1036920633849 = 312222^2 + 1018293^2 .

It is not a de Polignac number, because 1134403211133 - 2¹⁸ = 1134402948989 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1134403211097 and 1134403211106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1134403211113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1033153560 + ... + 1033154657.

It is an arithmetic number, because the mean of its divisors is an integer number (138787035309).

Almost surely, 2^{1134403211133} is an apocalyptic number.

It is an amenable number.

1134403211133 is a deficient number, since it is larger than the sum of its proper divisors (531041212575).

1134403211133 is a wasteful number, since it uses less digits than its factorization.

1134403211133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2066308284 (or 2066308281 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 1134403211133 its reverse (3311123044311), we get a palindrome (4445526255444).

The spelling of 1134403211133 in words is "one trillion, one hundred thirty-four billion, four hundred three million, two hundred eleven thousand, one hundred thirty-three".