Base | Representation |
---|---|
bin | 10000100000011111101… |
… | …101101000010001110111 |
3 | 11000110002112011122112202 |
4 | 100200133231220101313 |
5 | 122041224233440203 |
6 | 2225045430135115 |
7 | 144646400661245 |
oct | 20403755502167 |
9 | 4013075148482 |
10 | 1134403421303 |
11 | 3a8109180689 |
12 | 163a314b149b |
13 | 82c875306b9 |
14 | 3cc9667b795 |
15 | 1e795e8c388 |
hex | 1081fb68477 |
1134403421303 has 4 divisors (see below), whose sum is σ = 1135802193288. Its totient is φ = 1133004649320.
The previous prime is 1134403421287. The next prime is 1134403421317. The reversal of 1134403421303 is 3031243044311.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1134403421303 - 24 = 1134403421287 is a prime.
It is a super-2 number, since 2×11344034213032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1134403421363) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 699384776 + ... + 699386397.
It is an arithmetic number, because the mean of its divisors is an integer number (283950548322).
Almost surely, 21134403421303 is an apocalyptic number.
1134403421303 is a deficient number, since it is larger than the sum of its proper divisors (1398771985).
1134403421303 is an equidigital number, since it uses as much as digits as its factorization.
1134403421303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1398771984.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 1134403421303 its reverse (3031243044311), we get a palindrome (4165646465614).
The spelling of 1134403421303 in words is "one trillion, one hundred thirty-four billion, four hundred three million, four hundred twenty-one thousand, three hundred three".
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