Base | Representation |
---|---|
bin | 10101001000010110… |
… | …00111010001101011 |
3 | 1002021121022201200121 |
4 | 22210023013101223 |
5 | 141213120431103 |
6 | 5113403544111 |
7 | 551060025115 |
oct | 124413072153 |
9 | 32247281617 |
10 | 11344311403 |
11 | 48a1628077 |
12 | 224722b037 |
13 | 10ba36b4c9 |
14 | 7988da3b5 |
15 | 465e026bd |
hex | 2a42c746b |
11344311403 has 2 divisors, whose sum is σ = 11344311404. Its totient is φ = 11344311402.
The previous prime is 11344311373. The next prime is 11344311439. The reversal of 11344311403 is 30411344311.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11344311403 - 25 = 11344311371 is a prime.
It is not a weakly prime, because it can be changed into another prime (11344311203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5672155701 + 5672155702.
It is an arithmetic number, because the mean of its divisors is an integer number (5672155702).
Almost surely, 211344311403 is an apocalyptic number.
11344311403 is a deficient number, since it is larger than the sum of its proper divisors (1).
11344311403 is an equidigital number, since it uses as much as digits as its factorization.
11344311403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 11344311403 its reverse (30411344311), we get a palindrome (41755655714).
The spelling of 11344311403 in words is "eleven billion, three hundred forty-four million, three hundred eleven thousand, four hundred three".
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