Base | Representation |
---|---|
bin | 1010010100010100110110… |
… | …1100011100001001100101 |
3 | 1111011111122121122211122111 |
4 | 2211011031230130021211 |
5 | 2441331122400432010 |
6 | 40043301031201021 |
7 | 2250412426016620 |
oct | 245051554341145 |
9 | 44144577584574 |
10 | 11344312124005 |
11 | 36841064a28a3 |
12 | 133272b216171 |
13 | 6439c17aac83 |
14 | 2b30d3846db7 |
15 | 14a1591cb58a |
hex | a514db1c265 |
11344312124005 has 16 divisors (see below), whose sum is σ = 15680417034240. Its totient is φ = 7717705252992.
The previous prime is 11344312124003. The next prime is 11344312124029. The reversal of 11344312124005 is 50042121344311.
It is a happy number.
It is not a de Polignac number, because 11344312124005 - 21 = 11344312124003 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11344312124003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1276071160 + ... + 1276080049.
It is an arithmetic number, because the mean of its divisors is an integer number (980026064640).
Almost surely, 211344312124005 is an apocalyptic number.
It is an amenable number.
11344312124005 is a deficient number, since it is larger than the sum of its proper divisors (4336104910235).
11344312124005 is a wasteful number, since it uses less digits than its factorization.
11344312124005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2552151348.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 11344312124005 its reverse (50042121344311), we get a palindrome (61386433468316).
The spelling of 11344312124005 in words is "eleven trillion, three hundred forty-four billion, three hundred twelve million, one hundred twenty-four thousand, five".
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