Base | Representation |
---|---|
bin | 11001110010110101000011… |
… | …111001100100001111111011 |
3 | 112212200011002002210112220201 |
4 | 121302311003321210033323 |
5 | 104332132014222302103 |
6 | 1041135301013303031 |
7 | 32616031544505244 |
oct | 3162650371441773 |
9 | 485604062715821 |
10 | 113444110353403 |
11 | 331684168a3695 |
12 | 1088228b034a77 |
13 | 4b3b96cc4080b |
14 | 2002a1d445ccb |
15 | d1ae1d10951d |
hex | 672d43e643fb |
113444110353403 has 4 divisors (see below), whose sum is σ = 118376462977488. Its totient is φ = 108511757729320.
The previous prime is 113444110353397. The next prime is 113444110353419. The reversal of 113444110353403 is 304353011444311.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113444110353403 - 29 = 113444110352891 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113444110353443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2466176312008 + ... + 2466176312053.
It is an arithmetic number, because the mean of its divisors is an integer number (29594115744372).
Almost surely, 2113444110353403 is an apocalyptic number.
113444110353403 is a deficient number, since it is larger than the sum of its proper divisors (4932352624085).
113444110353403 is an equidigital number, since it uses as much as digits as its factorization.
113444110353403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4932352624084.
The product of its (nonzero) digits is 103680, while the sum is 37.
Adding to 113444110353403 its reverse (304353011444311), we get a palindrome (417797121797714).
The spelling of 113444110353403 in words is "one hundred thirteen trillion, four hundred forty-four billion, one hundred ten million, three hundred fifty-three thousand, four hundred three".
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