Base | Representation |
---|---|
bin | 10000100000100010000… |
… | …101000010011010010011 |
3 | 11000110012021212011001122 |
4 | 100200202011002122103 |
5 | 122041314414041313 |
6 | 2225053404552455 |
7 | 144650362230641 |
oct | 20404205023223 |
9 | 4013167764048 |
10 | 1134443112083 |
11 | 3a812961a986 |
12 | 163a4285272b |
13 | 82c92819578 |
14 | 3cc9ba50191 |
15 | 1e7996cc708 |
hex | 10822142693 |
1134443112083 has 2 divisors, whose sum is σ = 1134443112084. Its totient is φ = 1134443112082.
The previous prime is 1134443111999. The next prime is 1134443112169. The reversal of 1134443112083 is 3802113444311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1134443112083 - 214 = 1134443095699 is a prime.
It is a super-2 number, since 2×11344431120832 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1134443117083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567221556041 + 567221556042.
It is an arithmetic number, because the mean of its divisors is an integer number (567221556042).
Almost surely, 21134443112083 is an apocalyptic number.
1134443112083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134443112083 is an equidigital number, since it uses as much as digits as its factorization.
1134443112083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 35.
Adding to 1134443112083 its reverse (3802113444311), we get a palindrome (4936556556394).
The spelling of 1134443112083 in words is "one trillion, one hundred thirty-four billion, four hundred forty-three million, one hundred twelve thousand, eighty-three".
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