Base | Representation |
---|---|
bin | 10000100000100010000… |
… | …101000011101000011011 |
3 | 11000110012021212101220211 |
4 | 100200202011003220123 |
5 | 122041314414221313 |
6 | 2225053405031551 |
7 | 144650362251343 |
oct | 20404205035033 |
9 | 4013167771824 |
10 | 1134443117083 |
11 | 3a8129623711 |
12 | 163a428555b7 |
13 | 82c9281b923 |
14 | 3cc9ba51d23 |
15 | 1e7996cde3d |
hex | 10822143a1b |
1134443117083 has 2 divisors, whose sum is σ = 1134443117084. Its totient is φ = 1134443117082.
The previous prime is 1134443117081. The next prime is 1134443117179. The reversal of 1134443117083 is 3807113444311.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1134443117083 - 21 = 1134443117081 is a prime.
It is a super-2 number, since 2×11344431170832 (a number of 25 digits) contains 22 as substring.
Together with 1134443117081, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1134443117081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567221558541 + 567221558542.
It is an arithmetic number, because the mean of its divisors is an integer number (567221558542).
Almost surely, 21134443117083 is an apocalyptic number.
1134443117083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134443117083 is an equidigital number, since it uses as much as digits as its factorization.
1134443117083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 40.
The spelling of 1134443117083 in words is "one trillion, one hundred thirty-four billion, four hundred forty-three million, one hundred seventeen thousand, eighty-three".
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