113444400433 has 16 divisors (see below), whose sum is σ = 144438497280. Its totient is φ = 86663094336.

The previous prime is 113444400431. The next prime is 113444400599. The reversal of 113444400433 is 334004444311.

It is a happy number.

It is not a de Polignac number, because 113444400433 - 2¹ = 113444400431 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113444400395 and 113444400404.

It is not an unprimeable number, because it can be changed into a prime (113444400431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21491185 + ... + 21496462.

It is an arithmetic number, because the mean of its divisors is an integer number (9027406080).

Almost surely, 2^113444400433 is an apocalyptic number.

113444400433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

113444400433 is a deficient number, since it is larger than the sum of its proper divisors (30994096847).

113444400433 is a wasteful number, since it uses less digits than its factorization.

113444400433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42987696.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 113444400433 its reverse (334004444311), we get a palindrome (447448844744).

The spelling of 113444400433 in words is "one hundred thirteen billion, four hundred forty-four million, four hundred thousand, four hundred thirty-three".