1134721263853 has 4 divisors (see below), whose sum is σ = 1134734634688. Its totient is φ = 1134707893020.

The previous prime is 1134721263751. The next prime is 1134721263857. The reversal of 1134721263853 is 3583621274311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1134721263853 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1134721263857) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6557301 + ... + 6728122.

It is an arithmetic number, because the mean of its divisors is an integer number (283683658672).

Almost surely, 2^{1134721263853} is an apocalyptic number.

It is an amenable number.

1134721263853 is a deficient number, since it is larger than the sum of its proper divisors (13370835).

1134721263853 is an equidigital number, since it uses as much as digits as its factorization.

1134721263853 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13370834.

The product of its digits is 725760, while the sum is 46.

The spelling of 1134721263853 in words is "one trillion, one hundred thirty-four billion, seven hundred twenty-one million, two hundred sixty-three thousand, eight hundred fifty-three".