Base | Representation |
---|---|
bin | 110100110111001110… |
… | …1111110001101001001 |
3 | 101212000120121112112210 |
4 | 1221232131332031021 |
5 | 3324443230003200 |
6 | 124052421055333 |
7 | 11126123221665 |
oct | 1515635761511 |
9 | 355016545483 |
10 | 113522500425 |
11 | 44165545894 |
12 | 1a002557549 |
13 | a922213a99 |
14 | 56ccd5b8a5 |
15 | 2e4649b650 |
hex | 1a6e77e349 |
113522500425 has 12 divisors (see below), whose sum is σ = 187690534160. Its totient is φ = 60545333520.
The previous prime is 113522500373. The next prime is 113522500459. The reversal of 113522500425 is 524005225311.
It is not a de Polignac number, because 113522500425 - 27 = 113522500297 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 113522500392 and 113522500401.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 756816595 + ... + 756816744.
Almost surely, 2113522500425 is an apocalyptic number.
113522500425 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
113522500425 is a deficient number, since it is larger than the sum of its proper divisors (74168033735).
113522500425 is a wasteful number, since it uses less digits than its factorization.
113522500425 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1513633352 (or 1513633347 counting only the distinct ones).
The product of its (nonzero) digits is 12000, while the sum is 30.
Adding to 113522500425 its reverse (524005225311), we get a palindrome (637527725736).
The spelling of 113522500425 in words is "one hundred thirteen billion, five hundred twenty-two million, five hundred thousand, four hundred twenty-five".
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