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113523302540099 = 236180914684633
BaseRepresentation
bin11001110011111110110100…
…000111110010001101000011
3112212221201111010212110101102
4121303332310013302031003
5104334431210422240344
61041235515112525015
732624534160132104
oct3163766407621503
9485851433773342
10113523302540099
1133198a64812671
12108956b03b076b
134b462808b829a
1420067b2bc03ab
15d1d00570ae4e
hex673fb41f2343

113523302540099 has 8 divisors (see below), whose sum is σ = 120401050735392. Its totient is φ = 106807383714240.

The previous prime is 113523302539991. The next prime is 113523302540107. The reversal of 113523302540099 is 990045203325311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113523302540099 - 228 = 113523034104643 is a prime.

It is a super-2 number, since 2×1135233025400992 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113523302540699) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 40457340914 + ... + 40457343719.

It is an arithmetic number, because the mean of its divisors is an integer number (15050131341924).

Almost surely, 2113523302540099 is an apocalyptic number.

113523302540099 is a deficient number, since it is larger than the sum of its proper divisors (6877748195293).

113523302540099 is an equidigital number, since it uses as much as digits as its factorization.

113523302540099 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 80914684717.

The product of its (nonzero) digits is 874800, while the sum is 47.

The spelling of 113523302540099 in words is "one hundred thirteen trillion, five hundred twenty-three billion, three hundred two million, five hundred forty thousand, ninety-nine".

Divisors: 1 23 61 1403 80914684633 1861037746559 4935795762613 113523302540099