Base | Representation |
---|---|
bin | 11001110011111111100100… |
… | …010010000110010011000101 |
3 | 112212221210120110021121212221 |
4 | 121303333210102012103011 |
5 | 104334434334300101323 |
6 | 1041240131215212341 |
7 | 32624563201116526 |
oct | 3163774422062305 |
9 | 485853513247787 |
10 | 113524110550213 |
11 | 33199339924620 |
12 | 10895896b170b1 |
13 | 4b4637c11408c |
14 | 200684c23284d |
15 | d1d05161655d |
hex | 673fe44864c5 |
113524110550213 has 32 divisors (see below), whose sum is σ = 126950295098880. Its totient is φ = 100624238245440.
The previous prime is 113524110550157. The next prime is 113524110550219. The reversal of 113524110550213 is 312055011425311.
It is a cyclic number.
It is not a de Polignac number, because 113524110550213 - 225 = 113524076995781 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113524110550219) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 761530678 + ... + 761679736.
It is an arithmetic number, because the mean of its divisors is an integer number (3967196721840).
Almost surely, 2113524110550213 is an apocalyptic number.
It is an amenable number.
113524110550213 is a deficient number, since it is larger than the sum of its proper divisors (13426184548667).
113524110550213 is a wasteful number, since it uses less digits than its factorization.
113524110550213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 151969.
The product of its (nonzero) digits is 18000, while the sum is 34.
Adding to 113524110550213 its reverse (312055011425311), we get a palindrome (425579121975524).
The spelling of 113524110550213 in words is "one hundred thirteen trillion, five hundred twenty-four billion, one hundred ten million, five hundred fifty thousand, two hundred thirteen".
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