Base | Representation |
---|---|
bin | 10000100001010110011… |
… | …010011011100001111111 |
3 | 11000112110111000100101111 |
4 | 100201112122123201333 |
5 | 122100114202311411 |
6 | 2225320452022451 |
7 | 145011213265123 |
oct | 20412632334177 |
9 | 4015414010344 |
10 | 1135321135231 |
11 | 3a853a201748 |
12 | 164048901a27 |
13 | 830a26b9aaa |
14 | 3cd424c9583 |
15 | 1e7eb817721 |
hex | 1085669b87f |
1135321135231 has 2 divisors, whose sum is σ = 1135321135232. Its totient is φ = 1135321135230.
The previous prime is 1135321135199. The next prime is 1135321135253. The reversal of 1135321135231 is 1325311235311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1135321135231 - 25 = 1135321135199 is a prime.
It is a super-2 number, since 2×11353211352312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1135321135193 and 1135321135202.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1135321133231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567660567615 + 567660567616.
It is an arithmetic number, because the mean of its divisors is an integer number (567660567616).
Almost surely, 21135321135231 is an apocalyptic number.
1135321135231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1135321135231 is an equidigital number, since it uses as much as digits as its factorization.
1135321135231 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8100, while the sum is 31.
The spelling of 1135321135231 in words is "one trillion, one hundred thirty-five billion, three hundred twenty-one million, one hundred thirty-five thousand, two hundred thirty-one".
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