Base | Representation |
---|---|
bin | 100000111110001100001101… |
… | …110110101110100011100011 |
3 | 201000102221021210002120000001 |
4 | 200332030031312232203203 |
5 | 123001330431043440443 |
6 | 1232225122014440431 |
7 | 42354500022160252 |
oct | 4076141566564343 |
9 | 630387253076001 |
10 | 145011213265123 |
11 | 42228a014a9867 |
12 | 14320189b03117 |
13 | 62bb66394c38a |
14 | 27b4819dba799 |
15 | 11b711b376d4d |
hex | 83e30ddae8e3 |
145011213265123 has 8 divisors (see below), whose sum is σ = 152644419414800. Its totient is φ = 137378110818528.
The previous prime is 145011213265099. The next prime is 145011213265187. The reversal of 145011213265123 is 321562312110541.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 145011213265123 - 233 = 145002623330531 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (145011213235123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23047308 + ... + 28656601.
It is an arithmetic number, because the mean of its divisors is an integer number (19080552426850).
Almost surely, 2145011213265123 is an apocalyptic number.
145011213265123 is a deficient number, since it is larger than the sum of its proper divisors (7633206149677).
145011213265123 is a wasteful number, since it uses less digits than its factorization.
145011213265123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51851541.
The product of its (nonzero) digits is 43200, while the sum is 37.
Adding to 145011213265123 its reverse (321562312110541), we get a palindrome (466573525375664).
The spelling of 145011213265123 in words is "one hundred forty-five trillion, eleven billion, two hundred thirteen million, two hundred sixty-five thousand, one hundred twenty-three".
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