1135341203143 has 4 divisors (see below), whose sum is σ = 1297532803600. Its totient is φ = 973149602688.

The previous prime is 1135341203123. The next prime is 1135341203167. The reversal of 1135341203143 is 3413021435311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1135341203143 - 2¹³ = 1135341194951 is a prime.

It is a super-3 number, since 3×1135341203143³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1135341203123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81095800218 + ... + 81095800231.

It is an arithmetic number, because the mean of its divisors is an integer number (324383200900).

Almost surely, 2^{1135341203143} is an apocalyptic number.

1135341203143 is a deficient number, since it is larger than the sum of its proper divisors (162191600457).

1135341203143 is an equidigital number, since it uses as much as digits as its factorization.

1135341203143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 162191600456.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 1135341203143 its reverse (3413021435311), we get a palindrome (4548362638454).

The spelling of 1135341203143 in words is "one trillion, one hundred thirty-five billion, three hundred forty-one million, two hundred three thousand, one hundred forty-three".