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113534525105431 is a prime number
BaseRepresentation
bin11001110100001001010001…
…000010011110010100010111
3112212222210110021002211212021
4121310021101002132110113
5104340122201411333211
61041245012451234011
732625412241304343
oct3164112102362427
9485883407084767
10113534525105431
11331a27a3646051
12108979028a8907
134b4734b96aba1
142007159468623
15d1d460ab0771
hex67425109e517

113534525105431 has 2 divisors, whose sum is σ = 113534525105432. Its totient is φ = 113534525105430.

The previous prime is 113534525105411. The next prime is 113534525105459. The reversal of 113534525105431 is 134501525435311.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113534525105431 - 25 = 113534525105399 is a prime.

It is a super-3 number, since 3×1135345251054313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113534525105411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56767262552715 + 56767262552716.

It is an arithmetic number, because the mean of its divisors is an integer number (56767262552716).

Almost surely, 2113534525105431 is an apocalyptic number.

113534525105431 is a deficient number, since it is larger than the sum of its proper divisors (1).

113534525105431 is an equidigital number, since it uses as much as digits as its factorization.

113534525105431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540000, while the sum is 43.

The spelling of 113534525105431 in words is "one hundred thirteen trillion, five hundred thirty-four billion, five hundred twenty-five million, one hundred five thousand, four hundred thirty-one".