Base | Representation |
---|---|
bin | 11001110100001001101101… |
… | …010111101000110000100111 |
3 | 112212222211200101111002101102 |
4 | 121310021231113220300213 |
5 | 104340124140101242041 |
6 | 1041245131550550315 |
7 | 32625430102336331 |
oct | 3164115527506047 |
9 | 485884611432342 |
10 | 113535000415271 |
11 | 331a2a179793a6 |
12 | 10897a15b0839b |
13 | 4b473c6289b06 |
14 | 20071a2634451 |
15 | d1d48c69d09b |
hex | 67426d5e8c27 |
113535000415271 has 2 divisors, whose sum is σ = 113535000415272. Its totient is φ = 113535000415270.
The previous prime is 113535000415267. The next prime is 113535000415337. The reversal of 113535000415271 is 172514000535311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113535000415271 - 22 = 113535000415267 is a prime.
It is a super-3 number, since 3×1135350004152713 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113535000405271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56767500207635 + 56767500207636.
It is an arithmetic number, because the mean of its divisors is an integer number (56767500207636).
Almost surely, 2113535000415271 is an apocalyptic number.
113535000415271 is a deficient number, since it is larger than the sum of its proper divisors (1).
113535000415271 is an equidigital number, since it uses as much as digits as its factorization.
113535000415271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63000, while the sum is 38.
The spelling of 113535000415271 in words is "one hundred thirteen trillion, five hundred thirty-five billion, four hundred fifteen thousand, two hundred seventy-one".
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