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113535000415271 is a prime number
BaseRepresentation
bin11001110100001001101101…
…010111101000110000100111
3112212222211200101111002101102
4121310021231113220300213
5104340124140101242041
61041245131550550315
732625430102336331
oct3164115527506047
9485884611432342
10113535000415271
11331a2a179793a6
1210897a15b0839b
134b473c6289b06
1420071a2634451
15d1d48c69d09b
hex67426d5e8c27

113535000415271 has 2 divisors, whose sum is σ = 113535000415272. Its totient is φ = 113535000415270.

The previous prime is 113535000415267. The next prime is 113535000415337. The reversal of 113535000415271 is 172514000535311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113535000415271 - 22 = 113535000415267 is a prime.

It is a super-3 number, since 3×1135350004152713 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113535000405271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56767500207635 + 56767500207636.

It is an arithmetic number, because the mean of its divisors is an integer number (56767500207636).

Almost surely, 2113535000415271 is an apocalyptic number.

113535000415271 is a deficient number, since it is larger than the sum of its proper divisors (1).

113535000415271 is an equidigital number, since it uses as much as digits as its factorization.

113535000415271 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 63000, while the sum is 38.

The spelling of 113535000415271 in words is "one hundred thirteen trillion, five hundred thirty-five billion, four hundred fifteen thousand, two hundred seventy-one".