113535000415337 has 2 divisors, whose sum is σ = 113535000415338. Its totient is φ = 113535000415336.

The previous prime is 113535000415271. The next prime is 113535000415339. The reversal of 113535000415337 is 733514000535311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80403878846041 + 33131121569296 = 8966821^2 + 5755964^2 .

It is a cyclic number.

It is not a de Polignac number, because 113535000415337 - 2¹² = 113535000411241 is a prime.

It is a super-3 number, since 3×113535000415337³ (a number of 43 digits) contains 333 as substring.

Together with 113535000415339, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 113535000415294 and 113535000415303.

It is not a weakly prime, because it can be changed into another prime (113535000415339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56767500207668 + 56767500207669.

It is an arithmetic number, because the mean of its divisors is an integer number (56767500207669).

Almost surely, 2^{113535000415337} is an apocalyptic number.

It is an amenable number.

113535000415337 is a deficient number, since it is larger than the sum of its proper divisors (1).

113535000415337 is an equidigital number, since it uses as much as digits as its factorization.

113535000415337 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 283500, while the sum is 41.

The spelling of 113535000415337 in words is "one hundred thirteen trillion, five hundred thirty-five billion, four hundred fifteen thousand, three hundred thirty-seven".