Base | Representation |
---|---|
bin | 11001110100001001101101… |
… | …100111001110001010000011 |
3 | 112212222211200200011122102022 |
4 | 121310021231213032022003 |
5 | 104340124142123004421 |
6 | 1041245132214312055 |
7 | 32625430152143051 |
oct | 3164115547161203 |
9 | 485884620148368 |
10 | 113535004500611 |
11 | 331a2a1a209811 |
12 | 10897a1735862b |
13 | 4b473c708a485 |
14 | 20071a2db91d1 |
15 | d1d48cc087ab |
hex | 67426d9ce283 |
113535004500611 has 2 divisors, whose sum is σ = 113535004500612. Its totient is φ = 113535004500610.
The previous prime is 113535004500493. The next prime is 113535004500613. The reversal of 113535004500611 is 116005400535311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113535004500611 - 238 = 113260126593667 is a prime.
Together with 113535004500613, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (113535004500613) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56767502250305 + 56767502250306.
It is an arithmetic number, because the mean of its divisors is an integer number (56767502250306).
Almost surely, 2113535004500611 is an apocalyptic number.
113535004500611 is a deficient number, since it is larger than the sum of its proper divisors (1).
113535004500611 is an equidigital number, since it uses as much as digits as its factorization.
113535004500611 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27000, while the sum is 35.
The spelling of 113535004500611 in words is "one hundred thirteen trillion, five hundred thirty-five billion, four million, five hundred thousand, six hundred eleven".
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