Base | Representation |
---|---|
bin | 11001110100001001101101… |
… | …101001101000110111111111 |
3 | 112212222211200201100211201120 |
4 | 121310021231221220313333 |
5 | 104340124142303244320 |
6 | 1041245132240042023 |
7 | 32625430160422461 |
oct | 3164115551506777 |
9 | 485884621324646 |
10 | 113535005134335 |
11 | 331a2a1a601954 |
12 | 10897a17603313 |
13 | 4b473c724ca65 |
14 | 20071a3102131 |
15 | d1d48ccd1440 |
hex | 67426da68dff |
113535005134335 has 32 divisors (see below), whose sum is σ = 185089808636928. Its totient is φ = 59407480728960.
The previous prime is 113535005134321. The next prime is 113535005134351. The reversal of 113535005134335 is 533431500535311.
It is not a de Polignac number, because 113535005134335 - 213 = 113535005126143 is a prime.
It is a super-2 number, since 2×1135350051343352 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 20964420 + ... + 25818150.
It is an arithmetic number, because the mean of its divisors is an integer number (5784056519904).
Almost surely, 2113535005134335 is an apocalyptic number.
113535005134335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
113535005134335 is a deficient number, since it is larger than the sum of its proper divisors (71554803502593).
113535005134335 is a wasteful number, since it uses less digits than its factorization.
113535005134335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4883215.
The product of its (nonzero) digits is 607500, while the sum is 42.
Adding to 113535005134335 its reverse (533431500535311), we get a palindrome (646966505669646).
The spelling of 113535005134335 in words is "one hundred thirteen trillion, five hundred thirty-five billion, five million, one hundred thirty-four thousand, three hundred thirty-five".
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