Base | Representation |
---|---|
bin | 11001110100001110011110… |
… | …000000111101000110001110 |
3 | 112220000022212120221010011211 |
4 | 121310032132000331012032 |
5 | 104340220122022121032 |
6 | 1041251335051405034 |
7 | 32626000544116606 |
oct | 3164163600750616 |
9 | 486008776833154 |
10 | 113540111520142 |
11 | 331a50aaa7210a |
12 | 10898a0175377a |
13 | 4b47a2c149918 |
14 | 2007529377c06 |
15 | d1d68b24e747 |
hex | 67439e03d18e |
113540111520142 has 4 divisors (see below), whose sum is σ = 170310167280216. Its totient is φ = 56770055760070.
The previous prime is 113540111520131. The next prime is 113540111520323. The reversal of 113540111520142 is 241025111045311.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28385027880034 + ... + 28385027880037.
It is an arithmetic number, because the mean of its divisors is an integer number (42577541820054).
Almost surely, 2113540111520142 is an apocalyptic number.
113540111520142 is a deficient number, since it is larger than the sum of its proper divisors (56770055760074).
113540111520142 is an equidigital number, since it uses as much as digits as its factorization.
113540111520142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56770055760073.
The product of its (nonzero) digits is 4800, while the sum is 31.
Adding to 113540111520142 its reverse (241025111045311), we get a palindrome (354565222565453).
The spelling of 113540111520142 in words is "one hundred thirteen trillion, five hundred forty billion, one hundred eleven million, five hundred twenty thousand, one hundred forty-two".
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