Base | Representation |
---|---|
bin | 11001110100001111110001… |
… | …101000101000111110100100 |
3 | 112220000110111100202110000211 |
4 | 121310033301220220332210 |
5 | 104340231010143314140 |
6 | 1041252130204545204 |
7 | 32626050400512064 |
oct | 3164176150507644 |
9 | 486013440673024 |
10 | 113541514432420 |
11 | 331a575a96a948 |
12 | 10899133552204 |
13 | 4b47bc39a7b29 |
14 | 200761d8073a4 |
15 | d1d71e4bc2ea |
hex | 6743f1a28fa4 |
113541514432420 has 48 divisors (see below), whose sum is σ = 250772640104448. Its totient is φ = 43122279358080.
The previous prime is 113541514432393. The next prime is 113541514432427. The reversal of 113541514432420 is 24234415145311.
It is not an unprimeable number, because it can be changed into a prime (113541514432427) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1727622564 + ... + 1727688283.
It is an arithmetic number, because the mean of its divisors is an integer number (5224430002176).
Almost surely, 2113541514432420 is an apocalyptic number.
113541514432420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113541514432420 is an abundant number, since it is smaller than the sum of its proper divisors (137231125672028).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113541514432420 is a wasteful number, since it uses less digits than its factorization.
113541514432420 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3455310940 (or 3455310938 counting only the distinct ones).
The product of its (nonzero) digits is 230400, while the sum is 40.
Adding to 113541514432420 its reverse (24234415145311), we get a palindrome (137775929577731).
The spelling of 113541514432420 in words is "one hundred thirteen trillion, five hundred forty-one billion, five hundred fourteen million, four hundred thirty-two thousand, four hundred twenty".
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