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113544030431344 = 247096501901959
BaseRepresentation
bin11001110100010010000111…
…100110011010100001110000
3112220000200222201001102201011
4121310102013212122201300
5104340301133242300334
61041253224003320304
732626166631243652
oct3164220746324160
9486020881042634
10113544030431344
11331a68311010a7
1210899716080094
134b482050194a6
1420077bba206d2
15d1d81a308564
hex67448799a870

113544030431344 has 10 divisors (see below), whose sum is σ = 219991558960760. Its totient is φ = 56772015215664.

The previous prime is 113544030431339. The next prime is 113544030431347. The reversal of 113544030431344 is 443134030445311.

It is a junction number, because it is equal to n+sod(n) for n = 113544030431297 and 113544030431306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113544030431347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3548250950964 + ... + 3548250950995.

It is an arithmetic number, because the mean of its divisors is an integer number (21999155896076).

Almost surely, 2113544030431344 is an apocalyptic number.

It is an amenable number.

113544030431344 is a deficient number, since it is larger than the sum of its proper divisors (106447528529416).

113544030431344 is an equidigital number, since it uses as much as digits as its factorization.

113544030431344 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7096501901967 (or 7096501901961 counting only the distinct ones).

The product of its (nonzero) digits is 414720, while the sum is 40.

Adding to 113544030431344 its reverse (443134030445311), we get a palindrome (556678060876655).

The spelling of 113544030431344 in words is "one hundred thirteen trillion, five hundred forty-four billion, thirty million, four hundred thirty-one thousand, three hundred forty-four".

Divisors: 1 2 4 8 16 7096501901959 14193003803918 28386007607836 56772015215672 113544030431344