Base | Representation |
---|---|
bin | 11001110100010010001110… |
… | …001101001000011010000000 |
3 | 112220000201021102120022010210 |
4 | 121310102032031020122000 |
5 | 104340301400124302112 |
6 | 1041253243002354120 |
7 | 32626202445162012 |
oct | 3164221615103200 |
9 | 486021242508123 |
10 | 113544141244032 |
11 | 331a6888708334 |
12 | 108997471bb940 |
13 | 4b48221c77725 |
14 | 20077cc6281b2 |
15 | d1d824de6b3c |
hex | 67448e348680 |
113544141244032 has 32 divisors (see below), whose sum is σ = 301601625180480. Its totient is φ = 37848047081216.
The previous prime is 113544141243943. The next prime is 113544141244057. The reversal of 113544141244032 is 230442141445311.
It is a tau number, because it is divible by the number of its divisors (32).
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 147843933528 + ... + 147843934295.
It is an arithmetic number, because the mean of its divisors is an integer number (9425050786890).
Almost surely, 2113544141244032 is an apocalyptic number.
113544141244032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
113544141244032 is an abundant number, since it is smaller than the sum of its proper divisors (188057483936448).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113544141244032 is an equidigital number, since it uses as much as digits as its factorization.
113544141244032 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 295687867840 (or 295687867828 counting only the distinct ones).
The product of its (nonzero) digits is 184320, while the sum is 39.
Adding to 113544141244032 its reverse (230442141445311), we get a palindrome (343986282689343).
The spelling of 113544141244032 in words is "one hundred thirteen trillion, five hundred forty-four billion, one hundred forty-one million, two hundred forty-four thousand, thirty-two".
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