113544244540231 has 4 divisors (see below), whose sum is σ = 116184808366792. Its totient is φ = 110903680713672.

The previous prime is 113544244540213. The next prime is 113544244540283. The reversal of 113544244540231 is 132045442445311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113544244540231 - 2⁴¹ = 111345221284679 is a prime.

It is a super-2 number, since 2×113544244540231² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (43), and also a Moran number because the ratio is a prime number: 2640563826517 = 113544244540231 / (1 + 1 + 3 + 5 + 4 + 4 + 2 + 4 + 4 + 5 + 4 + 0 + 2 + 3 + 1).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113544244540931) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1320281913216 + ... + 1320281913301.

It is an arithmetic number, because the mean of its divisors is an integer number (29046202091698).

Almost surely, 2^{113544244540231} is an apocalyptic number.

113544244540231 is a deficient number, since it is larger than the sum of its proper divisors (2640563826561).

113544244540231 is an equidigital number, since it uses as much as digits as its factorization.

113544244540231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2640563826560.

The product of its (nonzero) digits is 921600, while the sum is 43.

Adding to 113544244540231 its reverse (132045442445311), we get a palindrome (245589686985542).

The spelling of 113544244540231 in words is "one hundred thirteen trillion, five hundred forty-four billion, two hundred forty-four million, five hundred forty thousand, two hundred thirty-one".