Base | Representation |
---|---|
bin | 1010010100111101000111… |
… | …1011001100101100111101 |
3 | 1111012112112212120020121011 |
4 | 2211033101323030230331 |
5 | 2442020241323114442 |
6 | 40052245332435221 |
7 | 2251244320614322 |
oct | 245172173145475 |
9 | 44175485506534 |
10 | 11355120519997 |
11 | 3688752562771 |
12 | 1334846a78b11 |
13 | 644a24acaa67 |
14 | 2b383b0bcb49 |
15 | 14a58d01e117 |
hex | a53d1eccb3d |
11355120519997 has 2 divisors, whose sum is σ = 11355120519998. Its totient is φ = 11355120519996.
The previous prime is 11355120519989. The next prime is 11355120520021. The reversal of 11355120519997 is 79991502155311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9136751562436 + 2218368957561 = 3022706^2 + 1489419^2 .
It is a cyclic number.
It is not a de Polignac number, because 11355120519997 - 23 = 11355120519989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11355120519947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5677560259998 + 5677560259999.
It is an arithmetic number, because the mean of its divisors is an integer number (5677560259999).
Almost surely, 211355120519997 is an apocalyptic number.
It is an amenable number.
11355120519997 is a deficient number, since it is larger than the sum of its proper divisors (1).
11355120519997 is an equidigital number, since it uses as much as digits as its factorization.
11355120519997 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3827250, while the sum is 58.
The spelling of 11355120519997 in words is "eleven trillion, three hundred fifty-five billion, one hundred twenty million, five hundred nineteen thousand, nine hundred ninety-seven".
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