Base | Representation |
---|---|
bin | 1010010100111101000111… |
… | …1011001100101101010101 |
3 | 1111012112112212120020122001 |
4 | 2211033101323030231111 |
5 | 2442020241323120041 |
6 | 40052245332435301 |
7 | 2251244320614355 |
oct | 245172173145525 |
9 | 44175485506561 |
10 | 11355120520021 |
11 | 3688752562793 |
12 | 1334846a78b31 |
13 | 644a24acaa85 |
14 | 2b383b0bcb65 |
15 | 14a58d01e131 |
hex | a53d1eccb55 |
11355120520021 has 2 divisors, whose sum is σ = 11355120520022. Its totient is φ = 11355120520020.
The previous prime is 11355120519997. The next prime is 11355120520027. The reversal of 11355120520021 is 12002502155311.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11334742957521 + 20377562500 = 3366711^2 + 142750^2 .
It is a cyclic number.
It is not a de Polignac number, because 11355120520021 - 25 = 11355120519989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11355120520027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5677560260010 + 5677560260011.
It is an arithmetic number, because the mean of its divisors is an integer number (5677560260011).
Almost surely, 211355120520021 is an apocalyptic number.
It is an amenable number.
11355120520021 is a deficient number, since it is larger than the sum of its proper divisors (1).
11355120520021 is an equidigital number, since it uses as much as digits as its factorization.
11355120520021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3000, while the sum is 28.
Adding to 11355120520021 its reverse (12002502155311), we get a palindrome (23357622675332).
The spelling of 11355120520021 in words is "eleven trillion, three hundred fifty-five billion, one hundred twenty million, five hundred twenty thousand, twenty-one".
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