Base | Representation |
---|---|
bin | 10101001001101010… |
… | …01100110010101111 |
3 | 1002022101002020122001 |
4 | 22210311030302233 |
5 | 141223432002142 |
6 | 5114440233131 |
7 | 551252555215 |
oct | 124465146257 |
9 | 32271066561 |
10 | 11355344047 |
11 | 48a7883063 |
12 | 224aa6b7a7 |
13 | 10bc7320b8 |
14 | 79a16ccb5 |
15 | 466d815b7 |
hex | 2a4d4ccaf |
11355344047 has 4 divisors (see below), whose sum is σ = 11366554680. Its totient is φ = 11344133416.
The previous prime is 11355344009. The next prime is 11355344057. The reversal of 11355344047 is 74044355311.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11355344047 - 211 = 11355341999 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11355343997 and 11355344015.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11355344057) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5603797 + ... + 5605822.
It is an arithmetic number, because the mean of its divisors is an integer number (2841638670).
Almost surely, 211355344047 is an apocalyptic number.
11355344047 is a deficient number, since it is larger than the sum of its proper divisors (11210633).
11355344047 is a wasteful number, since it uses less digits than its factorization.
11355344047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11210632.
The product of its (nonzero) digits is 100800, while the sum is 37.
Adding to 11355344047 its reverse (74044355311), we get a palindrome (85399699358).
The spelling of 11355344047 in words is "eleven billion, three hundred fifty-five million, three hundred forty-four thousand, forty-seven".
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