Base | Representation |
---|---|
bin | 11001110100011011100001… |
… | …000000010111011101001000 |
3 | 112220001200000212222222010122 |
4 | 121310123201000113131020 |
5 | 104340432314301410240 |
6 | 1041302013121202412 |
7 | 32630004650125061 |
oct | 3164334100273510 |
9 | 486050025888118 |
10 | 113554120341320 |
11 | 3320003964587a |
12 | 1089b671190408 |
13 | 4b49152526919 |
14 | 2008097aa9568 |
15 | d1dc0b0264b5 |
hex | 6746e1017748 |
113554120341320 has 64 divisors (see below), whose sum is σ = 259833685032000. Its totient is φ = 44650679442688.
The previous prime is 113554120341269. The next prime is 113554120341323. The reversal of 113554120341320 is 23143021455311.
It is not an unprimeable number, because it can be changed into a prime (113554120341323) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 97761479 + ... + 98916201.
It is an arithmetic number, because the mean of its divisors is an integer number (4059901328625).
Almost surely, 2113554120341320 is an apocalyptic number.
113554120341320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113554120341320 is an abundant number, since it is smaller than the sum of its proper divisors (146279564690680).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113554120341320 is a wasteful number, since it uses less digits than its factorization.
113554120341320 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1196462 (or 1196458 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 113554120341320 its reverse (23143021455311), we get a palindrome (136697141796631).
The spelling of 113554120341320 in words is "one hundred thirteen trillion, five hundred fifty-four billion, one hundred twenty million, three hundred forty-one thousand, three hundred twenty".
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