113554241420143 has 4 divisors (see below), whose sum is σ = 113730842107288. Its totient is φ = 113377640733000.

The previous prime is 113554241420131. The next prime is 113554241420149. The reversal of 113554241420143 is 341024142455311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113554241420143 is a prime.

It is a super-2 number, since 2×113554241420143² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113554241420096 and 113554241420105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113554241420149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88300342608 + ... + 88300343893.

It is an arithmetic number, because the mean of its divisors is an integer number (28432710526822).

Almost surely, 2^{113554241420143} is an apocalyptic number.

113554241420143 is a deficient number, since it is larger than the sum of its proper divisors (176600687145).

113554241420143 is an equidigital number, since it uses as much as digits as its factorization.

113554241420143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 176600687144.

The product of its (nonzero) digits is 230400, while the sum is 40.

Adding to 113554241420143 its reverse (341024142455311), we get a palindrome (454578383875454).

The spelling of 113554241420143 in words is "one hundred thirteen trillion, five hundred fifty-four billion, two hundred forty-one million, four hundred twenty thousand, one hundred forty-three".