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113554455450143 is a prime number
BaseRepresentation
bin11001110100011011110100…
…111110101101001000011111
3112220001200220020120021000112
4121310123310332231020133
5104340434011043401033
61041302110251520235
732630016156401531
oct3164336476551037
9486050806507015
10113554455450143
11332001a081a014
121089b74545907b
134b491a6a97b76
1420080ca3bb851
15d1dc2a66cc48
hex6746f4fad21f

113554455450143 has 2 divisors, whose sum is σ = 113554455450144. Its totient is φ = 113554455450142.

The previous prime is 113554455450113. The next prime is 113554455450173. The reversal of 113554455450143 is 341054554455311.

It is a balanced prime because it is at equal distance from previous prime (113554455450113) and next prime (113554455450173).

It is a cyclic number.

It is not a de Polignac number, because 113554455450143 - 210 = 113554455449119 is a prime.

It is a super-2 number, since 2×1135544554501432 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113554455450091 and 113554455450100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113554455450113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56777227725071 + 56777227725072.

It is an arithmetic number, because the mean of its divisors is an integer number (56777227725072).

Almost surely, 2113554455450143 is an apocalyptic number.

113554455450143 is a deficient number, since it is larger than the sum of its proper divisors (1).

113554455450143 is an equidigital number, since it uses as much as digits as its factorization.

113554455450143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7200000, while the sum is 50.

The spelling of 113554455450143 in words is "one hundred thirteen trillion, five hundred fifty-four billion, four hundred fifty-five million, four hundred fifty thousand, one hundred forty-three".