Base | Representation |
---|---|
bin | 110100111010110001… |
… | …1100011101001001000 |
3 | 101212022212100111221221 |
4 | 1221311203203221020 |
5 | 3330214144430000 |
6 | 124112305411424 |
7 | 11132066001364 |
oct | 1516543435110 |
9 | 355285314857 |
10 | 113641405000 |
11 | 44216679632 |
12 | 1a036339b74 |
13 | a940a46216 |
14 | 5700a702a4 |
15 | 2e51b3761a |
hex | 1a758e3a48 |
113641405000 has 80 divisors (see below), whose sum is σ = 266581854000. Its totient is φ = 45401928000.
The previous prime is 113641404983. The next prime is 113641405021. The reversal of 113641405000 is 504146311.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is an unprimeable number.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 4281771 + ... + 4308229.
It is an arithmetic number, because the mean of its divisors is an integer number (3332273175).
Almost surely, 2113641405000 is an apocalyptic number.
113641405000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 113641405000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (133290927000).
113641405000 is an abundant number, since it is smaller than the sum of its proper divisors (152940449000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113641405000 is an equidigital number, since it uses as much as digits as its factorization.
113641405000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27344 (or 27325 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 25.
The spelling of 113641405000 in words is "one hundred thirteen billion, six hundred forty-one million, four hundred five thousand".
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