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11375111147 is a prime number
BaseRepresentation
bin10101001100000001…
…00110101111101011
31002100202021111222212
422212000212233223
5141244012024042
65120424035335
7551612564231
oct124600465753
932322244885
1011375111147
114907a54404
122255602b4b
1310c38634ca
1479ca36951
15468988482
hex2a6026beb

11375111147 has 2 divisors, whose sum is σ = 11375111148. Its totient is φ = 11375111146.

The previous prime is 11375111123. The next prime is 11375111149. The reversal of 11375111147 is 74111157311.

11375111147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (74111157311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11375111147 is a prime.

Together with 11375111149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11375111149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5687555573 + 5687555574.

It is an arithmetic number, because the mean of its divisors is an integer number (5687555574).

Almost surely, 211375111147 is an apocalyptic number.

11375111147 is a deficient number, since it is larger than the sum of its proper divisors (1).

11375111147 is an equidigital number, since it uses as much as digits as its factorization.

11375111147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2940, while the sum is 32.

Adding to 11375111147 its reverse (74111157311), we get a palindrome (85486268458).

The spelling of 11375111147 in words is "eleven billion, three hundred seventy-five million, one hundred eleven thousand, one hundred forty-seven".