Base | Representation |
---|---|
bin | 10101001100000001… |
… | …00110101111101011 |
3 | 1002100202021111222212 |
4 | 22212000212233223 |
5 | 141244012024042 |
6 | 5120424035335 |
7 | 551612564231 |
oct | 124600465753 |
9 | 32322244885 |
10 | 11375111147 |
11 | 4907a54404 |
12 | 2255602b4b |
13 | 10c38634ca |
14 | 79ca36951 |
15 | 468988482 |
hex | 2a6026beb |
11375111147 has 2 divisors, whose sum is σ = 11375111148. Its totient is φ = 11375111146.
The previous prime is 11375111123. The next prime is 11375111149. The reversal of 11375111147 is 74111157311.
11375111147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (74111157311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11375111147 is a prime.
Together with 11375111149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11375111149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5687555573 + 5687555574.
It is an arithmetic number, because the mean of its divisors is an integer number (5687555574).
Almost surely, 211375111147 is an apocalyptic number.
11375111147 is a deficient number, since it is larger than the sum of its proper divisors (1).
11375111147 is an equidigital number, since it uses as much as digits as its factorization.
11375111147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2940, while the sum is 32.
Adding to 11375111147 its reverse (74111157311), we get a palindrome (85486268458).
The spelling of 11375111147 in words is "eleven billion, three hundred seventy-five million, one hundred eleven thousand, one hundred forty-seven".
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