Search a number
-
+
1138338740933 is a prime number
BaseRepresentation
bin10000100100001010010…
…001101011101011000101
311000211020210011121012122
4100210022101223223011
5122122304204202213
62230540125455325
7145146044435312
oct20441221535305
94024223147178
101138338740933
113a98485a7559
1216474b411545
13834639269b4
143d14b195d09
151e9266d7d08
hex1090a46bac5

1138338740933 has 2 divisors, whose sum is σ = 1138338740934. Its totient is φ = 1138338740932.

The previous prime is 1138338740881. The next prime is 1138338740983. The reversal of 1138338740933 is 3390478338311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1132230067969 + 6108672964 = 1064063^2 + 78158^2 .

It is an emirp because it is prime and its reverse (3390478338311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1138338740933 - 218 = 1138338478789 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1138338740983) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 569169370466 + 569169370467.

It is an arithmetic number, because the mean of its divisors is an integer number (569169370467).

Almost surely, 21138338740933 is an apocalyptic number.

It is an amenable number.

1138338740933 is a deficient number, since it is larger than the sum of its proper divisors (1).

1138338740933 is an equidigital number, since it uses as much as digits as its factorization.

1138338740933 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3919104, while the sum is 53.

The spelling of 1138338740933 in words is "one trillion, one hundred thirty-eight billion, three hundred thirty-eight million, seven hundred forty thousand, nine hundred thirty-three".