1140000304013 has 2 divisors, whose sum is σ = 1140000304014. Its totient is φ = 1140000304012.

The previous prime is 1140000303991. The next prime is 1140000304031. The reversal of 1140000304013 is 3104030000411.

Together with next prime (1140000304031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 779727852484 + 360272451529 = 883022^2 + 600227^2 .

It is a cyclic number.

It is not a de Polignac number, because 1140000304013 - 2¹⁰ = 1140000302989 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1140000303982 and 1140000304000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1140000304213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570000152006 + 570000152007.

It is an arithmetic number, because the mean of its divisors is an integer number (570000152007).

Almost surely, 2^{1140000304013} is an apocalyptic number.

It is an amenable number.

1140000304013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140000304013 is an equidigital number, since it uses as much as digits as its factorization.

1140000304013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1140000304013 its reverse (3104030000411), we get a palindrome (4244030304424).

The spelling of 1140000304013 in words is "one trillion, one hundred forty billion, three hundred four thousand, thirteen".