114000534303533 has 4 divisors (see below), whose sum is σ = 114344946794208. Its totient is φ = 113656121812860.

The previous prime is 114000534303479. The next prime is 114000534303559. The reversal of 114000534303533 is 335303435000411.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 114000534303533 - 2¹⁸ = 114000534041389 is a prime.

It is a super-2 number, since 2×114000534303533² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 114000534303493 and 114000534303502.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114000534303433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 172206244841 + ... + 172206245502.

It is an arithmetic number, because the mean of its divisors is an integer number (28586236698552).

Almost surely, 2^{114000534303533} is an apocalyptic number.

It is an amenable number.

114000534303533 is a deficient number, since it is larger than the sum of its proper divisors (344412490675).

114000534303533 is an equidigital number, since it uses as much as digits as its factorization.

114000534303533 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 344412490674.

The product of its (nonzero) digits is 97200, while the sum is 35.

Adding to 114000534303533 its reverse (335303435000411), we get a palindrome (449303969303944).

The spelling of 114000534303533 in words is "one hundred fourteen trillion, five hundred thirty-four million, three hundred three thousand, five hundred thirty-three".