Base | Representation |
---|---|
bin | 11001111010111011110100… |
… | …111100010001111011010001 |
3 | 112221122101211212012020011212 |
4 | 121322323310330101323101 |
5 | 104420243304120210301 |
6 | 1042243221411545505 |
7 | 33004211211421514 |
oct | 3172736474217321 |
9 | 487571755166155 |
10 | 114001131413201 |
11 | 3336267675229a |
12 | 109522242bb295 |
13 | 4b7c3505c8b56 |
14 | 2021981638d7b |
15 | d2a66ebab4bb |
hex | 67aef4f11ed1 |
114001131413201 has 2 divisors, whose sum is σ = 114001131413202. Its totient is φ = 114001131413200.
The previous prime is 114001131413177. The next prime is 114001131413341. The reversal of 114001131413201 is 102314131100411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 113971082924176 + 30048489025 = 10675724^2 + 173345^2 .
It is a cyclic number.
It is not a de Polignac number, because 114001131413201 - 222 = 114001127218897 is a prime.
It is not a weakly prime, because it can be changed into another prime (114001131413801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57000565706600 + 57000565706601.
It is an arithmetic number, because the mean of its divisors is an integer number (57000565706601).
Almost surely, 2114001131413201 is an apocalyptic number.
It is an amenable number.
114001131413201 is a deficient number, since it is larger than the sum of its proper divisors (1).
114001131413201 is an equidigital number, since it uses as much as digits as its factorization.
114001131413201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 23.
Adding to 114001131413201 its reverse (102314131100411), we get a palindrome (216315262513612).
The spelling of 114001131413201 in words is "one hundred fourteen trillion, one billion, one hundred thirty-one million, four hundred thirteen thousand, two hundred one".
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