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114001312309 is a prime number
BaseRepresentation
bin110101000101100000…
…0011111101000110101
3101220020221120200222021
41222023000133220311
53331433313443214
6124212123433141
711144026111003
oct1521300375065
9356227520867
10114001312309
1144390850295
121a1169857b1
13a99a48aa21
145736799a73
152e7352b924
hex1a8b01fa35

114001312309 has 2 divisors, whose sum is σ = 114001312310. Its totient is φ = 114001312308.

The previous prime is 114001312307. The next prime is 114001312379. The reversal of 114001312309 is 903213100411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 76260479409 + 37740832900 = 276153^2 + 194270^2 .

It is an emirp because it is prime and its reverse (903213100411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114001312309 - 21 = 114001312307 is a prime.

It is a super-2 number, since 2×1140013123092 (a number of 23 digits) contains 22 as substring.

Together with 114001312307, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114001312307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57000656154 + 57000656155.

It is an arithmetic number, because the mean of its divisors is an integer number (57000656155).

Almost surely, 2114001312309 is an apocalyptic number.

It is an amenable number.

114001312309 is a deficient number, since it is larger than the sum of its proper divisors (1).

114001312309 is an equidigital number, since it uses as much as digits as its factorization.

114001312309 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

The spelling of 114001312309 in words is "one hundred fourteen billion, one million, three hundred twelve thousand, three hundred nine".