1140033000030 has 32 divisors (see below), whose sum is σ = 2736508579200. Its totient is φ = 303961091232.

The previous prime is 1140032999999. The next prime is 1140033000031. The reversal of 1140033000030 is 300003300411.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a junction number, because it is equal to n+sod(n) for n = 1140032999973 and 1140033000009.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1140033000031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2787240 + ... + 3169979.

It is an arithmetic number, because the mean of its divisors is an integer number (85515893100).

Almost surely, 2^{1140033000030} is an apocalyptic number.

1140033000030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1140033000030 is an abundant number, since it is smaller than the sum of its proper divisors (1596475579170).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1140033000030 is a wasteful number, since it uses less digits than its factorization.

1140033000030 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5963608.

The product of its (nonzero) digits is 108, while the sum is 15.

Adding to 1140033000030 its reverse (300003300411), we get a palindrome (1440036300441).

The spelling of 1140033000030 in words is "one trillion, one hundred forty billion, thirty-three million, thirty", and thus it is an aban number.