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1140033321311 = 4740575978809
BaseRepresentation
bin10000100101101111010…
…001111111100101011111
311000222121212211012110212
4100211233101333211133
5122134242012240221
62231420222323035
7145236042226013
oct20455721774537
94028555735425
101140033321311
113aa5380a8905
12164b42a2947b
1383673a26491
143d26c26a543
151e9c536ab5b
hex1096f47f95f

1140033321311 has 8 divisors (see below), whose sum is σ = 1164576527040. Its totient is φ = 1115502081408.

The previous prime is 1140033321263. The next prime is 1140033321367. The reversal of 1140033321311 is 1131233300411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1140033321311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1140033321391) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2798726 + ... + 3180083.

It is an arithmetic number, because the mean of its divisors is an integer number (145572065880).

Almost surely, 21140033321311 is an apocalyptic number.

1140033321311 is a deficient number, since it is larger than the sum of its proper divisors (24543205729).

1140033321311 is an equidigital number, since it uses as much as digits as its factorization.

1140033321311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5982913.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 1140033321311 its reverse (1131233300411), we get a palindrome (2271266621722).

The spelling of 1140033321311 in words is "one trillion, one hundred forty billion, thirty-three million, three hundred twenty-one thousand, three hundred eleven".

Divisors: 1 47 4057 190679 5978809 281004023 24256028113 1140033321311