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1140034440404 = 221190323944267
BaseRepresentation
bin10000100101101111010…
…110010000110011010100
311000222121221221001120202
4100211233112100303110
5122134242304043104
62231420302320032
7145236054566456
oct20455726206324
94028557831522
101140034440404
113aa5387a2682
12164b43289018
1383674028972
143d26c47c2d6
151e9c54dc51e
hex1096f590cd4

1140034440404 has 12 divisors (see below), whose sum is σ = 1995227963904. Its totient is φ = 569969307864.

The previous prime is 1140034440397. The next prime is 1140034440431. The reversal of 1140034440404 is 4040444300411.

It is a super-2 number, since 2×11400344404042 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11924522 + ... + 12019745.

It is an arithmetic number, because the mean of its divisors is an integer number (166268996992).

Almost surely, 21140034440404 is an apocalyptic number.

It is an amenable number.

1140034440404 is a deficient number, since it is larger than the sum of its proper divisors (855193523500).

1140034440404 is a wasteful number, since it uses less digits than its factorization.

1140034440404 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23956174 (or 23956172 counting only the distinct ones).

The product of its (nonzero) digits is 12288, while the sum is 29.

Adding to 1140034440404 its reverse (4040444300411), we get a palindrome (5180478740815).

The spelling of 1140034440404 in words is "one trillion, one hundred forty billion, thirty-four million, four hundred forty thousand, four hundred four".

Divisors: 1 2 4 11903 23806 47612 23944267 47888534 95777068 285008610101 570017220202 1140034440404