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114010011131 = 176706471243
BaseRepresentation
bin110101000101110000…
…1101011010111111011
3101220021112221122111212
41222023201223113323
53331443030324011
6124213034113335
711144163051002
oct1521341532773
9356245848455
10114010011131
11443957518a5
121a11987b84b
13a99c215263
1457379c1c39
152e7419908b
hex1a8b86b5fb

114010011131 has 4 divisors (see below), whose sum is σ = 120716482392. Its totient is φ = 107303539872.

The previous prime is 114010011127. The next prime is 114010011133. The reversal of 114010011131 is 131110010411.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114010011131 - 22 = 114010011127 is a prime.

It is a super-2 number, since 2×1140100111312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114010011133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3353235605 + ... + 3353235638.

It is an arithmetic number, because the mean of its divisors is an integer number (30179120598).

Almost surely, 2114010011131 is an apocalyptic number.

114010011131 is a deficient number, since it is larger than the sum of its proper divisors (6706471261).

114010011131 is an equidigital number, since it uses as much as digits as its factorization.

114010011131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6706471260.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 114010011131 its reverse (131110010411), we get a palindrome (245120021542).

The spelling of 114010011131 in words is "one hundred fourteen billion, ten million, eleven thousand, one hundred thirty-one".

Divisors: 1 17 6706471243 114010011131