Base | Representation |
---|---|
bin | 110101000101110010… |
… | …1011100110011000011 |
3 | 101220021121210212222202 |
4 | 1222023211130303003 |
5 | 3331443304000003 |
6 | 124213111223415 |
7 | 11144204340005 |
oct | 1521345346303 |
9 | 356247725882 |
10 | 114011000003 |
11 | 4439626784a |
12 | 1a11a077b6b |
13 | a99c4a03a4 |
14 | 5737b9c375 |
15 | 2e742e2088 |
hex | 1a8b95ccc3 |
114011000003 has 4 divisors (see below), whose sum is σ = 114048994008. Its totient is φ = 113973006000.
The previous prime is 114010999951. The next prime is 114011000009. The reversal of 114011000003 is 300000110411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 114011000003 - 216 = 114010934467 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114011000009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18992501 + ... + 18998502.
It is an arithmetic number, because the mean of its divisors is an integer number (28512248502).
Almost surely, 2114011000003 is an apocalyptic number.
114011000003 is a deficient number, since it is larger than the sum of its proper divisors (37994005).
114011000003 is an equidigital number, since it uses as much as digits as its factorization.
114011000003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37994004.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 114011000003 its reverse (300000110411), we get a palindrome (414011110414).
The spelling of 114011000003 in words is "one hundred fourteen billion, eleven million, three", and thus it is an aban number.
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