11401114013 has 2 divisors, whose sum is σ = 11401114014. Its totient is φ = 11401114012.

The previous prime is 11401114003. The next prime is 11401114061. The reversal of 11401114013 is 31041110411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6416330404 + 4984783609 = 80102^2 + 70603^2 .

It is a cyclic number.

It is not a de Polignac number, because 11401114013 - 2⁶ = 11401113949 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11401113982 and 11401114000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11401114003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5700557006 + 5700557007.

It is an arithmetic number, because the mean of its divisors is an integer number (5700557007).

Almost surely, 2^11401114013 is an apocalyptic number.

It is an amenable number.

11401114013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11401114013 is an equidigital number, since it uses as much as digits as its factorization.

11401114013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 11401114013 its reverse (31041110411), we get a palindrome (42442224424).

The spelling of 11401114013 in words is "eleven billion, four hundred one million, one hundred fourteen thousand, thirteen".